C#,C++实现微秒延时

C#,C++实现微秒延时

C# 一般很容易实现毫秒延时

1.加入命名空间：using System.Threading;
2.Thread.Sleep(1000); // 1000毫秒延时

C#实现微秒延时方法

1.加入命名空间：using System.Runtime.InteropServices;
2.代码如下：主要用到两个函数QueryPerformanceFrequency()和QueryPerformanceCounter();

[DllImport("kernel32.dll")]extern static short QueryPerformanceCounter(ref long x);[DllImport("kernel32.dll")]extern static short QueryPerformanceFrequency(ref long x);//定义延迟函数public void delay(long delay_Time){long stop_Value = 0;long start_Value = 0;long freq = 0;long n = 0;QueryPerformanceFrequency(ref freq);  //获取CPU频率long count = delay_Time * freq / 1000000;   //这里写成1000000就是微秒，写成1000就是毫秒QueryPerformanceCounter(ref start_Value); //获取初始前值while (n < count) //不能精确判定{QueryPerformanceCounter(ref stop_Value);//获取终止变量值n = stop_Value - start_Value;}}

C++延时写法

void Time::LoopDelay(U32 ticks)
{if (ticks) {LARGE_INTEGER litmp;LONGLONG QPart1, QPart2;double dfMinus, dfFreq, dfTim, dfSleep;dfSleep = (double)ticks / 1000;QueryPerformanceFrequency(&litmp);dfFreq = (double)litmp.QuadPart;// 獲得計數器的時鐘頻率QueryPerformanceCounter(&litmp);QPart1 = litmp.QuadPart;// 獲得初始值do{QueryPerformanceCounter(&litmp);QPart2 = litmp.QuadPart;//獲得中止值dfMinus = (double)(QPart2 - QPart1);dfTim = dfMinus / dfFreq;// 獲得對應的時間值，單位為秒k;} while (dfTim<dfSleep);}
}